Optimal. Leaf size=126 \[ -\frac {4 x}{a^4}+\frac {664 \sin (c+d x)}{105 a^4 d}-\frac {88 \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac {4 \sin (c+d x)}{a^4 d (1+\sec (c+d x))}-\frac {\sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac {12 \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3} \]
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Rubi [A]
time = 0.21, antiderivative size = 126, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 5, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.263, Rules used = {3902, 4105,
3872, 2717, 8} \begin {gather*} \frac {664 \sin (c+d x)}{105 a^4 d}-\frac {4 \sin (c+d x)}{a^4 d (\sec (c+d x)+1)}-\frac {88 \sin (c+d x)}{105 a^4 d (\sec (c+d x)+1)^2}-\frac {4 x}{a^4}-\frac {12 \sin (c+d x)}{35 a d (a \sec (c+d x)+a)^3}-\frac {\sin (c+d x)}{7 d (a \sec (c+d x)+a)^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 2717
Rule 3872
Rule 3902
Rule 4105
Rubi steps
\begin {align*} \int \frac {\cos (c+d x)}{(a+a \sec (c+d x))^4} \, dx &=-\frac {\sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac {\int \frac {\cos (c+d x) (-8 a+4 a \sec (c+d x))}{(a+a \sec (c+d x))^3} \, dx}{7 a^2}\\ &=-\frac {\sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac {12 \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac {\int \frac {\cos (c+d x) \left (-52 a^2+36 a^2 \sec (c+d x)\right )}{(a+a \sec (c+d x))^2} \, dx}{35 a^4}\\ &=-\frac {88 \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac {\sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac {12 \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac {\int \frac {\cos (c+d x) \left (-244 a^3+176 a^3 \sec (c+d x)\right )}{a+a \sec (c+d x)} \, dx}{105 a^6}\\ &=-\frac {88 \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac {\sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac {12 \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac {4 \sin (c+d x)}{d \left (a^4+a^4 \sec (c+d x)\right )}-\frac {\int \cos (c+d x) \left (-664 a^4+420 a^4 \sec (c+d x)\right ) \, dx}{105 a^8}\\ &=-\frac {88 \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac {\sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac {12 \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac {4 \sin (c+d x)}{d \left (a^4+a^4 \sec (c+d x)\right )}-\frac {4 \int 1 \, dx}{a^4}+\frac {664 \int \cos (c+d x) \, dx}{105 a^4}\\ &=-\frac {4 x}{a^4}+\frac {664 \sin (c+d x)}{105 a^4 d}-\frac {88 \sin (c+d x)}{105 a^4 d (1+\sec (c+d x))^2}-\frac {\sin (c+d x)}{7 d (a+a \sec (c+d x))^4}-\frac {12 \sin (c+d x)}{35 a d (a+a \sec (c+d x))^3}-\frac {4 \sin (c+d x)}{d \left (a^4+a^4 \sec (c+d x)\right )}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(263\) vs. \(2(126)=252\).
time = 0.46, size = 263, normalized size = 2.09 \begin {gather*} -\frac {\sec \left (\frac {c}{2}\right ) \sec ^7\left (\frac {1}{2} (c+d x)\right ) \left (29400 d x \cos \left (\frac {d x}{2}\right )+29400 d x \cos \left (c+\frac {d x}{2}\right )+17640 d x \cos \left (c+\frac {3 d x}{2}\right )+17640 d x \cos \left (2 c+\frac {3 d x}{2}\right )+5880 d x \cos \left (2 c+\frac {5 d x}{2}\right )+5880 d x \cos \left (3 c+\frac {5 d x}{2}\right )+840 d x \cos \left (3 c+\frac {7 d x}{2}\right )+840 d x \cos \left (4 c+\frac {7 d x}{2}\right )-60830 \sin \left (\frac {d x}{2}\right )+46130 \sin \left (c+\frac {d x}{2}\right )-46116 \sin \left (c+\frac {3 d x}{2}\right )+18060 \sin \left (2 c+\frac {3 d x}{2}\right )-19292 \sin \left (2 c+\frac {5 d x}{2}\right )+2100 \sin \left (3 c+\frac {5 d x}{2}\right )-3791 \sin \left (3 c+\frac {7 d x}{2}\right )-735 \sin \left (4 c+\frac {7 d x}{2}\right )-105 \sin \left (4 c+\frac {9 d x}{2}\right )-105 \sin \left (5 c+\frac {9 d x}{2}\right )\right )}{26880 a^4 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.10, size = 98, normalized size = 0.78
method | result | size |
derivativedivides | \(\frac {-\frac {\left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+\frac {7 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {23 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+49 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+\frac {16 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )}-64 \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d \,a^{4}}\) | \(98\) |
default | \(\frac {-\frac {\left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{7}+\frac {7 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {23 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+49 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+\frac {16 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )}-64 \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{8 d \,a^{4}}\) | \(98\) |
risch | \(-\frac {4 x}{a^{4}}-\frac {i {\mathrm e}^{i \left (d x +c \right )}}{2 a^{4} d}+\frac {i {\mathrm e}^{-i \left (d x +c \right )}}{2 a^{4} d}+\frac {4 i \left (525 \,{\mathrm e}^{6 i \left (d x +c \right )}+2625 \,{\mathrm e}^{5 i \left (d x +c \right )}+5950 \,{\mathrm e}^{4 i \left (d x +c \right )}+7420 \,{\mathrm e}^{3 i \left (d x +c \right )}+5397 \,{\mathrm e}^{2 i \left (d x +c \right )}+2149 \,{\mathrm e}^{i \left (d x +c \right )}+382\right )}{105 d \,a^{4} \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{7}}\) | \(134\) |
norman | \(\frac {-\frac {4 x}{a}+\frac {65 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{8 a d}+\frac {31 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{6 a d}-\frac {47 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{60 a d}+\frac {11 \left (\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{70 a d}-\frac {\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )}{56 a d}-\frac {4 x \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a^{3}}\) | \(137\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.54, size = 158, normalized size = 1.25 \begin {gather*} \frac {\frac {1680 \, \sin \left (d x + c\right )}{{\left (a^{4} + \frac {a^{4} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )} {\left (\cos \left (d x + c\right ) + 1\right )}} + \frac {\frac {5145 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {805 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {147 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac {15 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}}{a^{4}} - \frac {6720 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{4}}}{840 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 6.68, size = 162, normalized size = 1.29 \begin {gather*} -\frac {420 \, d x \cos \left (d x + c\right )^{4} + 1680 \, d x \cos \left (d x + c\right )^{3} + 2520 \, d x \cos \left (d x + c\right )^{2} + 1680 \, d x \cos \left (d x + c\right ) + 420 \, d x - {\left (105 \, \cos \left (d x + c\right )^{4} + 1184 \, \cos \left (d x + c\right )^{3} + 2636 \, \cos \left (d x + c\right )^{2} + 2236 \, \cos \left (d x + c\right ) + 664\right )} \sin \left (d x + c\right )}{105 \, {\left (a^{4} d \cos \left (d x + c\right )^{4} + 4 \, a^{4} d \cos \left (d x + c\right )^{3} + 6 \, a^{4} d \cos \left (d x + c\right )^{2} + 4 \, a^{4} d \cos \left (d x + c\right ) + a^{4} d\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {\int \frac {\cos {\left (c + d x \right )}}{\sec ^{4}{\left (c + d x \right )} + 4 \sec ^{3}{\left (c + d x \right )} + 6 \sec ^{2}{\left (c + d x \right )} + 4 \sec {\left (c + d x \right )} + 1}\, dx}{a^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.46, size = 112, normalized size = 0.89 \begin {gather*} -\frac {\frac {3360 \, {\left (d x + c\right )}}{a^{4}} - \frac {1680 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )} a^{4}} + \frac {15 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 147 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 805 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 5145 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{a^{28}}}{840 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.75, size = 137, normalized size = 1.09 \begin {gather*} -\frac {15\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-192\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )+1144\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-6112\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-1680\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )+3360\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\,\left (c+d\,x\right )}{840\,a^4\,d\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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